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Chemistry
Chemistry
Problem
Calculate the quantity of heat, in kilojoules, required to melt
18.0
g
18.0\,\text{g}
18.0
g
of ice at
0
∘
C
0\,^{\circ}\!\text{C}
0
∘
C
. (Molar mass of water
=
18.02
g mol
−
1
=18.02\,\text{g mol}^{-1}
=
18.02
g mol
−
1
; molar enthalpy of fusion
=
6.01
kJ mol
−
1
=6.01\,\text{kJ mol}^{-1}
=
6.01
kJ mol
−
1
.) a)
−
6.01
kJ
-6.01\,\text{kJ}
−
6.01
kJ
b)
6.01
kJ
6.01\,\text{kJ}
6.01
kJ
c)
0.334
kJ
0.334\,\text{kJ}
0.334
kJ
d)
108
kJ
108\,\text{kJ}
108
kJ
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