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Mathematics
Mathematics
Problem
For
f
(
x
)
=
x
f(x)=\sqrt{x}
f
(
x
)
=
x
(
x
>
0
)
(x>0)
(
x
>
0
)
, the derivative
f
′
(
x
)
f'(x)
f
′
(
x
)
obtained from first principles is a)
1
x
\dfrac{1}{\sqrt{x}}
x
1
b)
1
2
x
\dfrac{1}{2\sqrt{x}}
2
x
1
c)
x
2
\dfrac{\sqrt{x}}{2}
2
x
d)
1
4
x
\dfrac{1}{4\sqrt{x}}
4
x
1
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