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Mathematics
Problem
Consider the curve
x
=
4
t
1
+
t
2
,
y
=
1
−
t
2
1
+
t
2
x=\dfrac{4t}{1+t^{2}},\;y=\dfrac{1-t^{2}}{1+t^{2}}
x
=
1
+
t
2
4
t
,
y
=
1
+
t
2
1
−
t
2
. Which one of the following lines is tangent to the curve at the point corresponding to
t
=
1
t=1
t
=
1
? a)
x
+
2
y
=
2
x+2y = 2
x
+
2
y
=
2
b)
x
=
2
x=2
x
=
2
c)
y
=
0
y=0
y
=
0
d)
x
+
y
=
2
x+y = 2
x
+
y
=
2
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