16.-Linear-Algebra-by-Kenneth-Hoffman · Problem 9.5.6

Operators on Inner Product Spaces

Mathematics — Linear Algebra · cayley-transform

Problem

Let VV be a finite-dimensional complex inner product space and UU a unitary operator on VV such that Uα=αU\alpha = \alpha implies α=0\alpha = 0. Let f(z)=i(1+z)(1−z),z≠1f(z) = i\frac{(1+z)}{(1-z)}, \qquad z \neq 1 and show that (a) f(U)=i(I+U)(I−U)−1f(U) = i(I + U)(I - U)^{-1}; (b) f(U)f(U) is self-adjoint; (c) for every self-adjoint operator TT on VV, the operator U=(T−iI)(T+iI)−1U = (T - iI)(T + iI)^{-1} is unitary and such that T=f(U)T = f(U).

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