Determine the relativistic motion of a charge in parallel uniform electric and magnetic fields.
Solution: The magnetic field has no influence on the motion along the common direction of E and H (the z axis), which therefore occurs under the influence of the electric field alone; therefore according to §20 we find:
z=eEEkin,Ekin=E02+(ceEt)2.
For the motion in the xy plane we have the equation
p˙x=ceHvy,p˙y=−ceHvx,
or
dtd(px+ipy)=−iceH(vx+ivy)=−EkinieHc(px+ipy).
Consequently px+ipy=pte−iϕ, where pt is the constant value of the projection of the momentum on the xy plane, and the auxiliary quantity ϕ is defined by the relation dϕ=eHcdt/Ekin. The trajectory is a helix with radius cpt/eH and monotonically increasing step, along which the particle moves with decreasing angular velocity ϕ˙=eHc/Ekin and with a velocity along the z axis which tends toward the value c.