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Mathematics
Problem
The domain of definition of
f
(
x
)
=
sin
−
1
(
∣
x
−
1
∣
−
2
)
f(x) = \sin^{-1}(|x-1|-2)
f
(
x
)
=
sin
−
1
(
∣
x
−
1∣
−
2
)
is: (a)
[
−
2
,
0
]
∪
[
2
,
4
]
[-2, 0] \cup [2, 4]
[
−
2
,
0
]
∪
[
2
,
4
]
(b)
(
−
2
,
0
)
∪
(
2
,
4
)
(-2, 0) \cup (2, 4)
(
−
2
,
0
)
∪
(
2
,
4
)
(c)
[
−
2
,
0
]
∪
[
1
,
3
]
[-2, 0] \cup [1, 3]
[
−
2
,
0
]
∪
[
1
,
3
]
(d)
(
−
2
,
0
)
∪
(
1
,
3
)
(-2, 0) \cup (1, 3)
(
−
2
,
0
)
∪
(
1
,
3
)
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