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Problems
If
5
log
a
b
c
(
a
3
+
b
3
+
c
3
)
=
3
λ
(
1
+
log
3
(
a
b
c
)
log
3
(
a
b
c
)
)
5 \log_{abc}(a^3 + b^3 + c^3) = 3\lambda \left( \frac{1 + \log_3(abc)}{\log_3(abc)} \right)
5
lo
g
ab
c
(
a
3
+
b
3
+
c
3
)
=
3
λ
(
l
o
g
3
(
ab
c
)
1
+
l
o
g
3
(
ab
c
)
)
…
Problem
If
5
log
a
b
c
(
a
3
+
b
3
+
c
3
)
=
3
λ
(
1
+
log
3
(
a
b
c
)
log
3
(
a
b
c
)
)
5 \log_{abc}(a^3 + b^3 + c^3) = 3\lambda \left( \frac{1 + \log_3(abc)}{\log_3(abc)} \right)
5
lo
g
ab
c
(
a
3
+
b
3
+
c
3
)
=
3
λ
(
l
o
g
3
(
ab
c
)
1
+
l
o
g
3
(
ab
c
)
)
and
(
a
b
c
)
a
+
b
+
c
=
1
(abc)^{a+b+c} = 1
(
ab
c
)
a
+
b
+
c
=
1
and
λ
=
m
n
\lambda = \frac{m}{n}
λ
=
n
m
, where
m
m
m
and
n
n
n
are relative primes, the value of
∣
m
+
n
∣
+
∣
m
−
n
∣
|m+n| + |m-n|
∣
m
+
n
∣
+
∣
m
−
n
∣
is a. 8 b. 10 c. 12 d. 14
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