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Problem
Problem
Let
f
(
x
)
=
ln
(
2
x
−
x
2
)
+
sin
π
x
2
f(x) = \ln(2x - x^2) + \sin \frac{\pi x}{2}
f
(
x
)
=
ln
(
2
x
−
x
2
)
+
sin
2
π
x
. Then, a. graph of
f
f
f
is symmetrical about the line
x
=
1
x = 1
x
=
1
b. graph of
f
f
f
is symmetrical about the line
x
=
2
x = 2
x
=
2
c. maximum value of
f
f
f
is 1 d. minimum value of
f
f
f
does not exist
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