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Mathematics
Problem
Prove that
cos
(
90
∘
+
θ
)
sec
(
−
θ
)
tan
(
180
∘
−
θ
)
sec
(
360
∘
−
θ
)
sin
(
180
∘
+
θ
)
cot
(
90
∘
−
θ
)
=
−
1.
\frac{\cos(90^\circ + \theta) \sec(-\theta) \tan(180^\circ - \theta)}{\sec(360^\circ - \theta) \sin(180^\circ + \theta) \cot(90^\circ - \theta)} = -1.
sec
(
36
0
∘
−
θ
)
sin
(
18
0
∘
+
θ
)
cot
(
9
0
∘
−
θ
)
cos
(
9
0
∘
+
θ
)
sec
(
−
θ
)
tan
(
18
0
∘
−
θ
)
=
−
1.
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