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Physics
Physics
Problem
The electric field of a plane electromagnetic wave is given by
E
⃗
=
E
0
i
^
cos
(
k
z
)
cos
(
ω
t
)
\vec{E} = E_0 \hat{i} \cos(kz) \cos(\omega t)
E
=
E
0
i
^
cos
(
k
z
)
cos
(
ω
t
)
. The corresponding magnetic field is then given by: a.
B
⃗
=
E
0
C
j
^
sin
(
k
z
)
sin
(
ω
t
)
\vec{B} = \frac{E_0}{C} \hat{j} \sin(kz) \sin(\omega t)
B
=
C
E
0
j
^
sin
(
k
z
)
sin
(
ω
t
)
b.
B
⃗
=
E
0
C
j
^
sin
(
k
z
)
cos
(
ω
t
)
\vec{B} = \frac{E_0}{C} \hat{j} \sin(kz) \cos(\omega t)
B
=
C
E
0
j
^
sin
(
k
z
)
cos
(
ω
t
)
c.
B
⃗
=
E
0
C
j
^
cos
(
k
z
)
sin
(
ω
t
)
\vec{B} = \frac{E_0}{C} \hat{j} \cos(kz) \sin(\omega t)
B
=
C
E
0
j
^
cos
(
k
z
)
sin
(
ω
t
)
d.
B
⃗
=
E
0
C
k
^
sin
(
k
z
)
cos
(
ω
t
)
\vec{B} = \frac{E_0}{C} \hat{k} \sin(kz) \cos(\omega t)
B
=
C
E
0
k
^
sin
(
k
z
)
cos
(
ω
t
)
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