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CrCl
3
→
NH
4
OH
NH
4
Cl
(
A
)
→
H
2
O
Na
2
O
2
(
B
)
→
acetate
Lead
(
C
)
\text{CrCl}_3 \xrightarrow[\text{NH}_4\text{OH}]{\text{NH}_4\text{Cl}} (A) \xrightarrow[\text{H}_2\text{O}]{\text{Na}_2\text{O}_2} (B) \xrightarrow[\text{acetate}]{\text{Lead}} (C)
CrCl
3
NH
4
Cl
NH
4
OH
(
A
)
Na
2
O
2
H
2
O
(
B
)
Lead
acetate
(
C
)
…
Chemistry
Problem
CrCl
3
→
NH
4
OH
NH
4
Cl
(
A
)
→
H
2
O
Na
2
O
2
(
B
)
→
acetate
Lead
(
C
)
\text{CrCl}_3 \xrightarrow[\text{NH}_4\text{OH}]{\text{NH}_4\text{Cl}} (A) \xrightarrow[\text{H}_2\text{O}]{\text{Na}_2\text{O}_2} (B) \xrightarrow[\text{acetate}]{\text{Lead}} (C)
CrCl
3
NH
4
Cl
NH
4
OH
(
A
)
Na
2
O
2
H
2
O
(
B
)
Lead
acetate
(
C
)
In this reaction sequence, the compound (C) is: a. Na
2
CrO
4
b. Na
2
Cr
2
O
7
c. Cr(OH)
3
d. PbCrO
4
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