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Chemistry
Chemistry
Problem
For the overall redox process in a galvanic cell,
Cr
3
+
+
3
e
−
→
Cr
(
s
)
(
E
∘
=
0.25
V
)
,
\text{Cr}^{3+}+3\,e^- \rightarrow \text{Cr}(s) \quad (E^{\circ}=0.25\,\text{V}),
Cr
3
+
+
3
e
−
→
Cr
(
s
)
(
E
∘
=
0.25
V
)
,
the reaction quotient at a certain moment is
Q
=
15
Q = 15
Q
=
15
. Calculate the cell potential at 330 K. (Use
R
=
8.314
J mol
−
1
K
−
1
R = 8.314\,\text{J mol}^{-1}\text{K}^{-1}
R
=
8.314
J mol
−
1
K
−
1
and
F
=
9.65
×
10
4
C mol
−
1
F = 9.65\times10^{4}\,\text{C mol}^{-1}
F
=
9.65
×
1
0
4
C mol
−
1
.) a)
0.24
V
0.24\,\text{V}
0.24
V
b)
0.22
V
0.22\,\text{V}
0.22
V
c)
0.28
V
0.28\,\text{V}
0.28
V
d)
0.18
V
0.18\,\text{V}
0.18
V
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