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Mathematics
Problem
6. ABC is a triangle right angled at C . A line through the mid-point M of hypotenuse AB and parallel to BC intersects AC at D . Show that (i) D is the mid-point of AC (ii)
M
D
⊥
A
C
\mathrm{MD} \perp \mathrm{AC}
MD
⊥
AC
(iii)
C
M
=
M
A
=
1
2
A
B
\mathrm{CM}=\mathrm{MA}=\frac{1}{2} \mathrm{AB}
CM
=
MA
=
2
1
AB
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