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Mathematics
Mathematics
Problem
Solve the differential equation
(
1
+
y
2
)
+
(
x
−
e
tan
−
1
y
)
d
y
d
x
=
0
(1+y^2) + (x - e^{\tan^{-1}y}) \frac{dy}{dx} = 0
(
1
+
y
2
)
+
(
x
−
e
t
a
n
−
1
y
)
d
x
d
y
=
0
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