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Problem
Problem
Find the quadrants of the coordinate planes such that for each point
(
x
,
y
)
(x, y)
(
x
,
y
)
on these quadrants (where
x
≠
0
,
y
≠
0
x \neq 0, y \neq 0
x
=
0
,
y
=
0
), the equation;
sin
4
θ
x
+
cos
4
θ
y
=
1
x
+
y
is solvable for
θ
.
\frac{\sin^4 \theta}{x} + \frac{\cos^4 \theta}{y} = \frac{1}{x+y} \text{ is solvable for } \theta.
x
sin
4
θ
+
y
cos
4
θ
=
x
+
y
1
is solvable for
θ
.
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