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Problem
Problem
The three sides of a triangle are given by
(
x
2
−
y
2
)
(
2
x
+
3
y
−
6
)
=
0
(x^2 - y^2)(2x + 3y - 6) = 0
(
x
2
−
y
2
)
(
2
x
+
3
y
−
6
)
=
0
. If the point
(
−
2
,
a
)
(-2, a)
(
−
2
,
a
)
lies inside and
(
b
,
1
)
(b, 1)
(
b
,
1
)
lies outside the triangle, then a.
a
∈
(
2
,
10
3
)
;
b
∈
(
−
1
,
1
)
a \in \left(2, \frac{10}{3}\right); b \in (-1, 1)
a
∈
(
2
,
3
10
)
;
b
∈
(
−
1
,
1
)
b.
a
∈
(
−
2
,
10
3
)
;
b
∈
(
−
1
,
9
2
)
a \in \left(-2, \frac{10}{3}\right); b \in \left(-1, \frac{9}{2}\right)
a
∈
(
−
2
,
3
10
)
;
b
∈
(
−
1
,
2
9
)
c.
a
∈
(
1
,
10
3
)
;
b
∈
(
−
3
,
5
)
a \in \left(1, \frac{10}{3}\right); b \in (-3, 5)
a
∈
(
1
,
3
10
)
;
b
∈
(
−
3
,
5
)
d. None of these
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