Problem

Problem

If 4x3−3x−p=04x^3 - 3x - p = 0 , where −1≤p≤1-1 \le p \le 1 has unique root in [12,1]\left[\frac{1}{2}, 1\right] , then the root is a. cos⁡−1p3\frac{\cos^{-1} p}{3} b. cos⁡(13cos⁡−1p)\cos\left(\frac{1}{3}\cos^{-1} p\right) c. cos⁡(cos⁡−1p)\cos(\cos^{-1} p) d. None of these

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