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Mathematics
Mathematics
Problem
The sum of all real values of 'm' such that the equation
(
x
2
−
2
m
x
−
4
(
m
2
+
1
)
)
⋅
(
x
2
−
4
x
−
2
m
(
m
2
+
1
)
)
=
0
(x^2 - 2mx - 4(m^2+1)) \cdot (x^2 - 4x - 2m(m^2+1)) = 0
(
x
2
−
2
m
x
−
4
(
m
2
+
1
))
⋅
(
x
2
−
4
x
−
2
m
(
m
2
+
1
))
=
0
has exactly three different real roots is - - -
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