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Mathematics
Mathematics
Problem
A tangent
P
T
PT
P
T
is drawn to the circle
x
2
+
y
2
=
4
x^2 + y^2 = 4
x
2
+
y
2
=
4
at the point
P
(
3
,
1
)
P(\sqrt{3}, 1)
P
(
3
,
1
)
. A straight line
L
L
L
, perpendicular to
P
T
PT
P
T
, is a tangent to the circle
(
x
−
3
)
2
+
y
2
=
1
(x-3)^2 + y^2 = 1
(
x
−
3
)
2
+
y
2
=
1
. A common tangent of the two circles is a.
x
=
4
x = 4
x
=
4
b.
y
=
2
y = 2
y
=
2
c.
x
+
3
y
=
4
x + \sqrt{3}y = 4
x
+
3
y
=
4
d.
x
+
2
2
y
=
6
x + 2\sqrt{2}y = 6
x
+
2
2
y
=
6
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