Blundell Thermal Physics · Problem 34.4

Non-equilibrium thermodynamics

Physics — Statistical Mechanics · thermopower-entropy-per-carrier

Problem

(a) Explain why the thermopower is a measure of the entropy per carrier. (b) Consider a classical gas of charged particles and explain why the thermopower ϵ\epsilon should be of the order of kB/e=87 μV K−1k_\mathrm{B}/e = 87~\mu\mathrm{V\,K}^{-1} and be independent of temperature TT. (c) In a metal, the measured thermopower is much less than 87 μV K−187~\mu\mathrm{V\,K}^{-1} and decreases as the metal is cooled. Give an argument for why one might expect the thermopower to behave as ϵ≈kBekBTTF,(34.69)\epsilon \approx \frac{k_\mathrm{B}}{e}\frac{k_\mathrm{B}T}{T_\mathrm{F}},\tag{34.69} where TFT_\mathrm{F} is the Fermi temperature. (d) In a semiconductor, the measured thermopower is much larger than 87 μV K−187~\mu\mathrm{V\,K}^{-1} and increases as the metal is cooled. Give an argument for why one might expect the thermopower to behave as ϵ≈kBeEg2kBT,(34.70)\epsilon \approx \frac{k_\mathrm{B}}{e}\frac{E_\mathrm{g}}{2k_\mathrm{B}T},\tag{34.70} where EgE_\mathrm{g} is the energy gap of the semiconductor. (e) Since thermopower is a function of the entropy of the carriers, the third law of thermodynamics leads one to expect that it should go to zero as T→0T \to 0. Is this a problem for the semiconductor considered in (d)?

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