Problem

Problem

If ∣a∣<∣b∣|a| < |b|, b−a<1b - a < 1 and a,ba, b are the real roots of the equation x2−∣α∣x−∣β∣=0x^2 - |\alpha|x - |\beta| = 0, the equation log⁡∣b∣∣xa∣−1=0\log_{|b|} \left| \frac{x}{a} \right| - 1 = 0 has a. one root lying in interval (−∞,a)(-\infty, a) b. one root lying in interval (b,∞)(b, \infty) c. one positive root d. one negative root

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