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Mathematics
Mathematics
Problem
If
y
=
sin
−
1
(
sin
α
sin
x
1
−
cos
α
sin
x
)
y = \sin^{-1} \left( \frac{\sin \alpha \sin x}{1 - \cos \alpha \sin x} \right)
y
=
sin
−
1
(
1
−
c
o
s
α
s
i
n
x
s
i
n
α
s
i
n
x
)
, then
y
′
(
0
)
y'(0)
y
′
(
0
)
is equal to a. 1 b.
2
tan
α
2 \tan \alpha
2
tan
α
c.
(
1
2
)
tan
α
\left(\frac{1}{2}\right) \tan \alpha
(
2
1
)
tan
α
d.
sin
α
\sin \alpha
sin
α
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