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Mathematics
Mathematics
Problem
Prove that
1
+
sin
2
θ
1
−
sin
2
θ
=
(
1
+
tan
θ
1
−
tan
θ
)
2
\frac{1 + \sin 2\theta}{1 - \sin 2\theta} = \left( \frac{1 + \tan \theta}{1 - \tan \theta} \right)^2
1
−
s
i
n
2
θ
1
+
s
i
n
2
θ
=
(
1
−
t
a
n
θ
1
+
t
a
n
θ
)
2
.
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