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Problem Let f ( x ) = sec ( 3 x 2 + 1 ) f(x)=\sec\bigl(\sqrt{3x^{2}+1}\bigr) f ( x ) = sec ( 3 x 2 + 1 ) f ′ ( x ) f'(x) f ′ ( x ) 6 x sec ( 3 x 2 + 1 ) tan ( 3 x 2 + 1 ) 6x\,\sec\bigl(\sqrt{3x^{2}+1}\bigr)\tan\bigl(\sqrt{3x^{2}+1}\bigr) 6 x sec ( 3 x 2 + 1 ) tan ( 3 x 2 + 1 ) 3 x sec ( 3 x 2 + 1 ) tan ( 3 x 2 + 1 ) 3x\,\sec\bigl(\sqrt{3x^{2}+1}\bigr)\tan\bigl(\sqrt{3x^{2}+1}\bigr) 3 x sec ( 3 x 2 + 1 ) tan ( 3 x 2 + 1 ) 3 x sec ( 3 x 2 + 1 ) tan ( 3 x 2 + 1 ) 3 x 2 + 1 \displaystyle \frac{3x\,\sec\bigl(\sqrt{3x^{2}+1}\bigr)\tan\bigl(\sqrt{3x^{2}+1}\bigr)}{\sqrt{3x^{2}+1}} 3 x 2 + 1 3 x sec ( 3 x 2 + 1 ) tan ( 3 x 2 + 1 ) 3 x sec ( 3 x 2 + 1 ) cot ( 3 x 2 + 1 ) 3 x 2 + 1 \displaystyle \frac{3x\,\sec\bigl(\sqrt{3x^{2}+1}\bigr)\cot\bigl(\sqrt{3x^{2}+1}\bigr)}{\sqrt{3x^{2}+1}} 3 x 2 + 1 3 x sec ( 3 x 2 + 1 ) cot ( 3 x 2 + 1 ) Browse the problem library