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Problem If I n = ∫ cot n x d x I_n = \int \cot^n x\,dx I n = ∫ cot n x d x , then I 0 + I 1 + 2 ( I 2 + I 3 + ⋯ + I 8 ) + I 9 + I 10 I_0 + I_1 + 2\left(I_2 + I_3 + \dots + I_8\right) + I_9 + I_{10} I 0 + I 1 + 2 ( I 2 + I 3 + ⋯ + I 8 ) + I 9 + I 10 equals to (where u = cot x u = \cot x u = cot x )
a. u + u 2 2 + ⋯ + u 9 9 u + \frac{u^2}{2} + \dots + \frac{u^9}{9} u + 2 u 2 + ⋯ + 9 u 9
b. − ( u + u 2 2 + ⋯ + u 9 9 ) - \left( u + \frac{u^2}{2} + \dots + \frac{u^9}{9} \right) − ( u + 2 u 2 + ⋯ + 9 u 9 )
c. − ( u + u 2 2 ! + ⋯ + u 9 9 ! ) - \left( u + \frac{u^2}{2!} + \dots + \frac{u^9}{9!} \right) − ( u + 2 ! u 2 + ⋯ + 9 ! u 9 )
d. u 2 + 2 u 2 3 + ⋯ + 9 u 9 10 \frac{u}{2} + \frac{2u^2}{3} + \dots + \frac{9u^9}{10} 2 u + 3 2 u 2 + ⋯ + 10 9 u 9
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