Mathematics

Problem

If the given lines

\frac{x-1}{-3} = \frac{y-2}{2k} = \frac{z-3}{2}

and

\frac{x-1}{3k} = \frac{y-1}{1} = \frac{z-6}{-5}

are perpendicular, then

k

is (A)

-10

(B)

\frac{10}{7}

(C)

-\frac{10}{7}

(D)

-\frac{7}{10}