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Mathematics
Mathematics
Problem
A particle has acceleration
a
(
t
)
=
⟨
e
t
,
cos
t
⟩
\mathbf a(t)=\langle e^{t},\cos t\rangle
a
(
t
)
=
⟨
e
t
,
cos
t
⟩
. Its velocity at
t
=
0
t=0
t
=
0
is
v
(
0
)
=
⟨
2
,
−
1
⟩
\mathbf v(0)=\langle 2,-1\rangle
v
(
0
)
=
⟨
2
,
−
1
⟩
, and its position at
t
=
π
t=\pi
t
=
π
is
r
(
π
)
=
⟨
5
,
4
⟩
\mathbf r(\pi)=\langle 5,4\rangle
r
(
π
)
=
⟨
5
,
4
⟩
. What is
r
(
0
)
\mathbf r(0)
r
(
0
)
? a)
⟨
6
−
e
π
+
π
,
2
−
π
⟩
\langle 6-e^{\pi}+\pi,\,2-\pi\rangle
⟨
6
−
e
π
+
π
,
2
−
π
⟩
b)
⟨
6
−
e
π
−
π
,
2
+
π
⟩
\langle 6-e^{\pi}-\pi,\,2+\pi\rangle
⟨
6
−
e
π
−
π
,
2
+
π
⟩
c)
⟨
6
−
e
π
,
2
⟩
\langle 6-e^{\pi},\,2\rangle
⟨
6
−
e
π
,
2
⟩
d)
⟨
6
−
e
π
−
π
,
6
+
π
⟩
\langle 6-e^{\pi}-\pi,\,6+\pi\rangle
⟨
6
−
e
π
−
π
,
6
+
π
⟩
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