Introduction to Classical Mechanics · Problem 6.34

The Lagrangian method — Morin

Physics — Mechanics · principle-of-stationary-action

Problem

x¨\ddot{x} dependence * Assume that there is x¨\ddot{x} dependence (in addition to xx, x˙\dot{x}, tt dependence) in the Lagrangian in Theorem 6.1. There will then be the additional term (∂L/∂x¨a)β¨(\partial L/\partial \ddot{x}_a)\ddot{\beta} in Eq. (6.19). It is tempting to integrate this term by parts twice, and then arrive at a modified form of Eq. (6.22): ∂L∂x0−ddt(∂L∂x˙0)+d2dt2(∂L∂x¨0)=0.\frac{\partial L}{\partial x_0} - \frac{d}{dt}\left(\frac{\partial L}{\partial \dot{x}_0}\right) + \frac{d^2}{dt^2}\left(\frac{\partial L}{\partial \ddot{x}_0}\right) = 0. Is this a valid result? If not, where is the error in the reasoning?

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