Canonical Quantization of Scalar Fields — Mark Srednicki
Physics — QFT · muon-decay-rate
Problem
Consider the process of muon decay, μ−→e−νˉeνμ. In section 88, we will compute ∣T∣2 for this process (summed over the possible spin states of the decay products, and averaged over the possible spin states of the initial muon), with the result
∣T∣2=64GF2(k1⋅k2′)(k1′⋅k3′),(11.52)
where GF is the Fermi constant, k1 is the four-momentum of the muon, and k1,2,3′ are the four-momenta of the νˉe, νμ, and e−, respectively. In the rest frame of the muon, its decay rate is therefore
Γ=m32GF2∫(k1⋅k2′)(k1′⋅k3′)dLIPS3(k1),(11.53)
where k1=(m,0), and m is the muon mass. The neutrinos are massless, and the electron mass is 200 times less than the muon mass, so we can take the electron to be massless as well. To evaluate Γ, we perform the following analysis.
a) Show that
Γ=m32GF2∫dk3′k1μk3ν′∫k2′μk1′νdLIPS2(k1−k3′).(11.54)
b) Use Lorentz invariance to argue that, for m1′=m2′=0,
∫k1′μk2′νdLIPS2(k)=Ak2gμν+Bkμkν,(11.55)
where A and B are numerical constants.
c) Show that, for m1′=m2′=0,
∫dLIPS2(k)=8π1.(11.56)
d) By contracting both sides of eq. (11.55) with gμν and with kμkν, and using eq. (11.56), evaluate A and B.
e) Use the results of parts (b) and (d) in eq. (11.54). Set k1=(m,0), and compute dΓ/dEe; here Ee≡E3′ is the energy of the electron. Note that the maximum value of Ee is reached when the electron is emitted in one direction, and the two neutrinos in the opposite direction; what is this maximum value?
f) Perform the integral over Ee to obtain the muon decay rate Γ.
g) The measured lifetime of the muon is 2.197×10−6s. The muon mass is 105.66MeV. Determine the value of GF in GeV−2. (Your answer is too low by about 0.2\%, due to loop corrections to the decay rate.)
h) Define the energy spectrum of the electron P(Ee)≡Γ−1dΓ/dEe. Note that P(Ee)dEe is the probability for the electron to be emitted with energy between Ee and Ee+dEe. Draw a graph of P(Ee) vs.Ee/mμ.