Chemistry

Chemistry

Problem

The rate constant for the forward reaction A(g)⇌2B(g)A (g) \rightleftharpoons 2B (g) is 1.5×10−3s−11.5 \times 10^{-3} s^{-1} at 100 K. If 10−510^{-5} moles of A and 100 moles of B are present in a 10 litre vessel at equilibrium then rate constant for the backward reaction at this temperature is : (A) 1.50×104Lmol−1s−11.50 \times 10^{4} L mol^{-1} s^{-1} (B) 1.5×1011Lmol−1s−11.5 \times 10^{11} L mol^{-1} s^{-1} (C) 1.5×1010Lmol−1s−11.5 \times 10^{10} L mol^{-1} s^{-1} (D) 1.5×10−11Lmol−1s−11.5 \times 10^{-11} L mol^{-1} s^{-1}

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