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Mathematics
Mathematics
Problem
Prove that
sin
3
θ
=
3
sin
θ
−
4
sin
3
θ
\sin3\theta=3\sin\theta-4\sin^{3}\theta\,
sin
3
θ
=
3
sin
θ
−
4
sin
3
θ
for any real number
θ
\theta
θ
.
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