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Problem
Problem
Evaluate
lim
h
→
0
log
e
(
1
+
2
h
)
−
2
log
e
(
1
+
h
)
h
2
\lim_{h \to 0} \frac{\log_e(1+2h) - 2 \log_e(1+h)}{h^2}
lim
h
→
0
h
2
l
o
g
e
(
1
+
2
h
)
−
2
l
o
g
e
(
1
+
h
)
.
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