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Mathematics
Problem
Let
f
(
x
)
=
x
2
−
25
x
−
5
f(x)=\dfrac{x^{2}-25}{x-5}
f
(
x
)
=
x
−
5
x
2
−
25
for
x
≠
5
x\ne 5
x
=
5
. Determine the value that should be assigned to
f
(
5
)
f(5)
f
(
5
)
so that
f
f
f
becomes continuous at
x
=
5
x=5
x
=
5
.
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