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Mathematics
Mathematics
Problem
11. Show that
∣
a
⃗
∣
b
⃗
+
∣
b
⃗
∣
a
⃗
|\vec{a}| \vec{b}+|\vec{b}| \vec{a}
∣
a
∣
b
+
∣
b
∣
a
is perpendicular to
∣
a
⃗
∣
b
⃗
−
∣
b
⃗
∣
a
⃗
|\vec{a}| \vec{b}-|\vec{b}| \vec{a}
∣
a
∣
b
−
∣
b
∣
a
, for any two nonzero vectors
a
⃗
\vec{a}
a
and
b
⃗
\vec{b}
b
.
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