An Introduction to Modern Astrophysics · Problem 12.7

Main-Sequence and Post-Main-Sequence Stellar Evolution — Carroll & Ostlie

Physics — Astrophysics · molecular-rotational-energy

Problem

The rotational kinetic energy of a molecule is given by Erot=12Iω2=L22I,E_{\mathrm{rot}} = \frac{1}{2}I\omega^2 = \frac{L^2}{2I}, where LL is the molecule's angular momentum and II is its moment of inertia. The angular momentum is restricted by quantum mechanics to the discrete values L=ℓ(ℓ+1)ℏL = \sqrt{\ell(\ell+1)}\hbar where ℓ=0,1,2,…\ell = 0, 1, 2, \ldots (a) For a diatomic molecule, I=m1r12+m2r22,I = m_1 r_1^2 + m_2 r_2^2, where m1m_1 and m2m_2 are the masses of the individual atoms and r1r_1 and r2r_2 are their separations from the center of mass of the molecule. Using the ideas developed in Section 2.3, show that II may be written as I=μr2,I = \mu r^2, where μ\mu is the reduced mass and rr is the separation between the atoms in the molecule. (b) The separation between the carbon and oxygen atoms in CO is approximately 0.12 nm, and the atomic masses of 12^{12}C, 13^{13}C, and 16^{16}O are 12.000 u, 13.003 u, and 15.995 u, respectively. Calculate the moments of inertia for 12^{12}CO and 13^{13}CO. (c) What is the wavelength of the photon that is emitted by 12^{12}CO during a transition between the rotational angular momentum states ℓ=3\ell = 3 and ℓ=2\ell = 2? To which part of the electromagnetic spectrum does this correspond? (d) Repeat part (c) for 13^{13}CO. How do astronomers distinguish among different isotopes in the interstellar medium?

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