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Mathematics
Mathematics
Problem
Find the value of
∑
k
=
1
10
(
8
−
3
k
)
+
∑
k
=
11
20
(
2
k
−
5
)
\displaystyle \sum_{k=1}^{10} (8 - 3k) + \sum_{k=11}^{20} (2k - 5)
k
=
1
∑
10
(
8
−
3
k
)
+
k
=
11
∑
20
(
2
k
−
5
)
. a)
195
195
195
b)
175
175
175
c)
155
155
155
d)
225
225
225
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