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Mathematics
Problem
- If
4
x
2
+
λ
y
2
=
45
4x^2 + \lambda y^2 = 45
4
x
2
+
λ
y
2
=
45
and
x
2
−
4
y
2
=
5
x^2 - 4y^2 = 5
x
2
−
4
y
2
=
5
cut orthogonally, then the value of
λ
\lambda
λ
is a.
1
9
\frac{1}{9}
9
1
b.
1
3
\frac{1}{3}
3
1
c. 9 d. 18
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