Two Lorentz transformations differ by an infinitesimal amount. In the notation of Section 11.7 they are represented by A1=eL, A2=eL+δL. Without using explicit matrix representations show that to first order in δL the Lorentz transformation A=A2A1−1 can be written as
A=I+δL+2!1[L,δL]+3!1[L,[L,δL]]+4!1[L,[L,[L,δL]]]+⋯
Hint: The early terms can be found by brute force, but alternatively consider the Taylor series expansion in λ of the operator A(λ)=eλ(L+δL)e−λL and then put λ=1.