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Mathematics
Problem
Find the points on the curve where tangents to the curve
y
2
−
2
x
3
−
4
y
+
8
=
0
pass through
(
1
,
2
)
.
y^2 - 2x^3 - 4y + 8 = 0 \text{ pass through } (1, 2).
y
2
−
2
x
3
−
4
y
+
8
=
0
pass through
(
1
,
2
)
.
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