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Problem
Problem
a
t
2
+
7
2
t
−
4
=
0
at^2 + \frac{7}{2}t - 4 = 0
a
t
2
+
2
7
t
−
4
=
0
The above equation has solutions at
t
=
−
8
t=-8
t
=
−
8
and
t
=
1
t=1
t
=
1
. What is the value of the constant
a
a
a
?
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