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Problem Solve for all θ \theta θ 0 ≤ θ < 2 π 0\le \theta<2\pi 0 ≤ θ < 2 π cos 3 θ = − 1 2 \cos 3\theta=-\dfrac{1}{2} cos 3 θ = − 2 1 θ = 2 π 9 , 4 π 9 , 8 π 9 , 10 π 9 , 14 π 9 \theta=\dfrac{2\pi}{9},\,\dfrac{4\pi}{9},\,\dfrac{8\pi}{9},\,\dfrac{10\pi}{9},\,\dfrac{14\pi}{9} θ = 9 2 π , 9 4 π , 9 8 π , 9 10 π , 9 14 π θ = π 9 , 5 π 9 , 7 π 9 , 11 π 9 , 13 π 9 , 17 π 9 \theta=\dfrac{\pi}{9},\,\dfrac{5\pi}{9},\,\dfrac{7\pi}{9},\,\dfrac{11\pi}{9},\,\dfrac{13\pi}{9},\,\dfrac{17\pi}{9} θ = 9 π , 9 5 π , 9 7 π , 9 11 π , 9 13 π , 9 17 π θ = 2 π 9 , 4 π 9 , 8 π 9 , 10 π 9 , 14 π 9 , 16 π 9 \theta=\dfrac{2\pi}{9},\,\dfrac{4\pi}{9},\,\dfrac{8\pi}{9},\,\dfrac{10\pi}{9},\,\dfrac{14\pi}{9},\,\dfrac{16\pi}{9} θ = 9 2 π , 9 4 π , 9 8 π , 9 10 π , 9 14 π , 9 16 π θ = 2 π 9 , 8 π 9 , 14 π 9 \theta=\dfrac{2\pi}{9},\,\dfrac{8\pi}{9},\,\dfrac{14\pi}{9} θ = 9 2 π , 9 8 π , 9 14 π Browse the problem library