Introduction to Quantum Mechanics · Problem 6.37

Symmetries and Conservation Laws — David J. Griffiths

Physics — Quantum Mechanics · time_reversal_spin

Problem

As an angular momentum, a particle's spin must flip under time reversal (Problem 6.36). The action of time-reversal on a spinor (Section 4.4.1) is in fact Θ^(ab)=(−b∗a∗)(6.84)\hat{\Theta}\begin{pmatrix} a \\ b \end{pmatrix} = \begin{pmatrix} -b^* \\ a^* \end{pmatrix} \quad (6.84) so that, in addition to the complex conjugation, the up and down components are interchanged. (a) Show that Θ^2=−1\hat{\Theta}^2 = -1 for a spin-1/2 particle. (b) Consider an eigenstate ∣ψn⟩|\psi_n\rangle of a time-reversal invariant Hamiltonian (Equation 6.83) with energy EnE_n. We know that ∣ψn′⟩=Θ^∣ψn⟩|\psi_n'\rangle = \hat{\Theta}|\psi_n\rangle is also an eigenstate of H^\hat{H} with the same energy EnE_n. There are two possibilities: either ∣ψn′⟩|\psi_n'\rangle and ∣ψn⟩|\psi_n\rangle are the same state (meaning ∣ψn′⟩=c∣ψn⟩|\psi_n'\rangle = c|\psi_n\rangle for some complex constant cc) or they are distinct states. Show that the first case leads to a contradiction in the case of a spin-1/2 particle, meaning the energy level must be (at least) two-fold degenerate in that case. *Comment:* What you have proved is a special case of Kramer's degeneracy: for an odd number of spin-1/2 particles (or any half-integer spin for that matter), every energy level (of a time-reversal-invariant Hamiltonian) is at least two-fold degenerate. This is because—as you just showed—for half-integer spin a state and its time-reversed state are necessarily distinct.

Related theory

Browse the problem library