Linear Algebra Done Right · Problem 7B.11

Operators on Inner Product Spaces — Sheldon Axler

Mathematics — Linear Algebra · spectral-theorem

Problem

Prove that every self-adjoint operator on VV has a cube root. An operator S∈L(V)S \in \mathcal{L}(V) is called a cube root of T∈L(V)T \in \mathcal{L}(V) if S3=TS^3 = T.

Related theory

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