Mathematics

Mathematics

Problem

The angle made by the tangent of the curve x=a(t+sin⁡tcos⁡t)x = a(t + \sin t \cos t), y=a(1+sin⁡t)2y = a(1 + \sin t)^2 with the xx-axis at any point on it is (a) 14(π+2t)\frac{1}{4}(\pi + 2t) (b) 1−sin⁡tcos⁡t\frac{1 - \sin t}{\cos t} (c) 14(2t−π)\frac{1}{4}(2t - \pi) (d) 1+sin⁡tcos⁡2t\frac{1 + \sin t}{\cos 2t} (a) 14(π+2t)\frac{1}{4}(\pi + 2t) (b) 1−sin⁡tcos⁡t\frac{1 - \sin t}{\cos t} (c) 14(2t−π)\frac{1}{4}(2t - \pi) (d) 1+sin⁡tcos⁡2t\frac{1 + \sin t}{\cos 2t}

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