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Mathematics
Problem
Two line whose equation are
x
−
3
2
=
y
−
2
3
=
z
−
1
λ
\frac{x-3}{2} = \frac{y-2}{3} = \frac{z-1}{\lambda}
2
x
−
3
=
3
y
−
2
=
λ
z
−
1
and
x
−
2
3
=
y
−
3
2
=
z
−
2
3
\frac{x-2}{3} = \frac{y-3}{2} = \frac{z-2}{3}
3
x
−
2
=
2
y
−
3
=
3
z
−
2
lie in the same plane, then.Point of intersection of the lines lies on a.
3
x
+
y
+
z
=
20
3x + y + z = 20
3
x
+
y
+
z
=
20
b.
2
x
+
y
+
z
=
25
2x + y + z = 25
2
x
+
y
+
z
=
25
c.
3
x
+
2
y
+
z
=
24
3x + 2y + z = 24
3
x
+
2
y
+
z
=
24
d.
x
=
y
=
z
x = y = z
x
=
y
=
z
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