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Mathematics
Mathematics
Problem
5. Find the vector equation of the line passing through the point
(
1
,
2
,
−
4
)
(1,2,-4)
(
1
,
2
,
−
4
)
and perpendicular to the two lines:
x
−
8
3
=
y
+
19
−
16
=
z
−
10
7
and
x
−
15
3
=
y
−
29
8
=
z
−
5
−
5
.
\frac{x-8}{3}=\frac{y+19}{-16}=\frac{z-10}{7} \text { and } \frac{x-15}{3}=\frac{y-29}{8}=\frac{z-5}{-5} .
3
x
−
8
=
−
16
y
+
19
=
7
z
−
10
and
3
x
−
15
=
8
y
−
29
=
−
5
z
−
5
.
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