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Physics
Physics
Problem
A small lamp filament can be treated as a blackbody of surface area
2.0
×
10
−
4
m
2
2.0 \times 10^{-4}\,\text{m}^{2}
2.0
×
1
0
−
4
m
2
. It radiates
500
W
500\,\text{W}
500
W
of power when steady. Using
σ
=
5.67
×
10
−
8
W
m
−
2
K
−
4
\sigma = 5.67 \times 10^{-8}\,\text{W}\,\text{m}^{-2}\,\text{K}^{-4}
σ
=
5.67
×
1
0
−
8
W
m
−
2
K
−
4
, estimate its steady temperature. a)
3.1
×
10
3
K
3.1 \times 10^{3}\,\text{K}
3.1
×
1
0
3
K
b)
2.6
×
10
3
K
2.6 \times 10^{3}\,\text{K}
2.6
×
1
0
3
K
c)
1.6
×
10
3
K
1.6 \times 10^{3}\,\text{K}
1.6
×
1
0
3
K
d)
2.0
×
10
3
K
2.0 \times 10^{3}\,\text{K}
2.0
×
1
0
3
K
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