Physics

Physics

Problem

A small lamp filament can be treated as a blackbody of surface area 2.0×10−4 m22.0 \times 10^{-4}\,\text{m}^{2}. It radiates 500 W500\,\text{W} of power when steady. Using σ=5.67×10−8 W m−2 K−4\sigma = 5.67 \times 10^{-8}\,\text{W}\,\text{m}^{-2}\,\text{K}^{-4}, estimate its steady temperature. a) 3.1×103 K3.1 \times 10^{3}\,\text{K} b) 2.6×103 K2.6 \times 10^{3}\,\text{K} c) 1.6×103 K1.6 \times 10^{3}\,\text{K} d) 2.0×103 K2.0 \times 10^{3}\,\text{K}

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