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Mathematics
Mathematics
Problem
For
x
∈
R
x \in R
x
∈
R
,
f
(
x
)
=
log
2
−
sin
x
f(x) = \log 2 - \sin x
f
(
x
)
=
lo
g
2
−
sin
x
and
g
(
x
)
=
f
(
f
(
x
)
)
g(x) = f(f(x))
g
(
x
)
=
f
(
f
(
x
))
, then a.
g
g
g
is not differentiable at
x
=
0
x = 0
x
=
0
b.
g
′
′
(
0
)
=
cos
(
log
2
)
g''(0) = \cos(\log 2)
g
′′
(
0
)
=
cos
(
lo
g
2
)
c.
g
′
′
(
0
)
=
−
cos
(
log
2
)
g''(0) = -\cos(\log 2)
g
′′
(
0
)
=
−
cos
(
lo
g
2
)
d.
g
g
g
is differentiable at
x
=
0
x = 0
x
=
0
and
g
′
′
(
0
)
=
−
sin
(
log
2
)
g''(0) = -\sin(\log 2)
g
′′
(
0
)
=
−
sin
(
lo
g
2
)
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