Chemistry

Chemistry

Problem

A reaction carried out under standard conditions has the following thermodynamic data: Ecell∘=+0.15 VE^\circ_{\text{cell}}=+0.15\,\text{V} and ΔH∘=+50 kJ mol−1\Delta H^\circ=+50\,\text{kJ\,mol}^{-1}. Which conclusion about the spontaneity of the reaction at 25 ∘C25\,^{\circ}\text{C} is most justified? a) The reaction is non-spontaneous because its positive ΔH∘\Delta H^\circ overrides the positive Ecell∘E^\circ_{\text{cell}}. b) No firm conclusion can be drawn without the value of ΔS∘\Delta S^\circ, since the positive ΔH∘\Delta H^\circ may offset a favorable Ecell∘E^\circ_{\text{cell}}. c) The reaction is spontaneous because Ecell∘E^\circ_{\text{cell}} is positive, so ΔG∘=−nFEcell∘<0\Delta G^\circ=-nF E^\circ_{\text{cell}}<0 even though ΔH∘\Delta H^\circ is positive. d) The reaction is non-spontaneous because a positive cell potential means work must be done on the system (ΔG∘=+nFEcell∘>0\Delta G^\circ = +nF E^\circ_{\text{cell}}>0).

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