Problem

Problem

Let PP be the point on the parabola y2=8xy^2 = 8x , which is at a minimum distance from the centre CC of the circle x2+(y+6)2=1x^2 + (y + 6)^2 = 1 , the equation of the circle passing through CC and having its centre at PP , is a. x2+y2−4x+8y+12=0x^2 + y^2 - 4x + 8y + 12 = 0 b. x2+y2−x+4y−12=0x^2 + y^2 - x + 4y - 12 = 0 c. x2+y2−x4+2y−24=0x^2 + y^2 - \frac{x}{4} + 2y - 24 = 0 d. x2+y2−4x+9y+18=0x^2 + y^2 - 4x + 9y + 18 = 0

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